What is the derivative of y= x/8-8/x ?

The derivative of y= x/8-8/x is 1/8+8/(x^2)

What is the first derivative of y= x/8-8/x ?

The first derivative of y= x/8-8/x is 1/8+8/(x^2)

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derivative of

y = \frac{x}{8} - \frac{8}{x}

\frac{1}{8} + \frac{8}{x ^{2}}

Solution steps

\frac{d}{d x} (\frac{x}{8} - \frac{8}{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{x}{8}) - \frac{d}{d x} (\frac{8}{x})

\frac{d}{d x} (\frac{x}{8}) = \frac{1}{8}

\frac{d}{d x} (\frac{8}{x}) = - \frac{8}{x ^{2}}

= \frac{1}{8} - (- \frac{8}{x ^{2}})

Simplify

= \frac{1}{8} + \frac{8}{x ^{2}}

What is the derivative of y= x/8-8/x ?
The derivative of y= x/8-8/x is 1/8+8/(x^2)
What is the first derivative of y= x/8-8/x ?
The first derivative of y= x/8-8/x is 1/8+8/(x^2)