What is the solution for (5y-2x)dy-2ydx=0 ?

The solution for (5y-2x)dy-2ydx=0 is y=(4x+sqrt(16x^2+c_{1)})/(10),y=(4x-sqrt(16x^2+c_{1)})/(10)

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(5y-2x)dy-2ydx=0

(5 y - 2 x) d y - 2 y d x = 0

y = \frac{4 x + 16 x ^{2} + c _{1}}{10}, y = \frac{4 x - 16 x ^{2} + c _{1}}{10}

Solution steps

(5 y - 2 x) d y - 2 y d x = 0

Solve exact ODE:

y = \frac{4 x + 16 x ^{2} + c _{1}}{10}, y = \frac{4 x - 16 x ^{2} + c _{1}}{10}

y = \frac{4 x + 16 x ^{2} + c _{1}}{10}, y = \frac{4 x - 16 x ^{2} + c _{1}}{10}

What is the solution for (5y-2x)dy-2ydx=0 ?
The solution for (5y-2x)dy-2ydx=0 is y=(4x+sqrt(16x^2+c_{1)})/(10),y=(4x-sqrt(16x^2+c_{1)})/(10)