What is the integral from-125 to 64 of 1/(x^{1/3)} ?

The integral from-125 to 64 of 1/(x^{1/3)} is -27/2

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integral from-125 to 64 of 1/(x^{1/3)}

\int_{- 125}^{64} \frac{1}{x ^{\frac{1}{3}}} d x

- \frac{27}{2}

Decimal

- 13.5

Solution steps

\int_{- 125}^{64} \frac{1}{x ^{\frac{1}{3}}} d x

Find undefined (singularity) points:

x = 0

If exist

b, a < b < c, f (b) =

undefined

, \int_{a}^{c} f (x) d x = \int_{a}^{b} f (x) d x + \int_{b}^{c} f (x) d x

= \int_{- 125}^{0} \frac{1}{x ^{\frac{1}{3}}} d x + \int_{0}^{64} \frac{1}{x ^{\frac{1}{3}}} d x

\int_{- 125}^{0} \frac{1}{x ^{\frac{1}{3}}} d x = - \frac{75 ( - 1 ) ^{\frac{2}{3}}}{2}

\int_{0}^{64} \frac{1}{x ^{\frac{1}{3}}} d x = 24

= - \frac{75 ( - 1 ) ^{\frac{2}{3}}}{2} + 24

Simplify

- \frac{75 ( - 1 ) ^{\frac{2}{3}}}{2} + 24 : - \frac{27}{2}

= - \frac{27}{2}

What is the integral from-125 to 64 of 1/(x^{1/3)} ?
The integral from-125 to 64 of 1/(x^{1/3)} is -27/2