y^'=y(3-y)

Lösung

y^{^{'}} = y (3 - y)

y = \frac{3}{- e ^{- 3 t - c_{1}} + 1}

Schritte zur Lösung

y^{'} (t) = y (3 - y)

Solve Bernoulli ODE:

y = \frac{3}{- e ^{- 3 t - c_{1}} + 1}

y = \frac{3}{- e ^{- 3 t - c_{1}} + 1}

\int 3^{\frac{x}{2}} d x

\frac{\partial}{\partial x} (7 yz ln (x))

t an g e n t y = \frac{3}{x}, (1, 3)

\int \frac{3 x + 1}{( x - 4 ) ( x - 2 )} d x

\frac{d}{d x} (\frac{x ^{2} - 8 x + 12}{( x - 4 ) ^{2}})