What is the solution for y^{''}+16y=16cos(4x) ?

The solution for y^{''}+16y=16cos(4x) is y=c_{1}cos(4x)+c_{2}sin(4x)+2xsin(4x)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

y^{''}+16y=16cos(4x)

y^{^{''}} + 16 y = 16 cos (4 x)

y = c_{1} cos (4 x) + c_{2} sin (4 x) + 2 x sin (4 x)

Solution steps

y^{''} (x) + 16 y = 16 cos (4 x)

Solve linear ODE:

y = c_{1} cos (4 x) + c_{2} sin (4 x) + 2 x sin (4 x)

y = c_{1} cos (4 x) + c_{2} sin (4 x) + 2 x sin (4 x)

What is the solution for y^{''}+16y=16cos(4x) ?
The solution for y^{''}+16y=16cos(4x) is y=c_{1}cos(4x)+c_{2}sin(4x)+2xsin(4x)