What is the derivative of 1+3cos(2x) ?

The derivative of 1+3cos(2x) is -6sin(2x)

What is the first derivative of 1+3cos(2x) ?

The first derivative of 1+3cos(2x) is -6sin(2x)

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\frac{d}{d x} (1 + 3 cos (2 x))

- 6 sin (2 x)

Solution steps

\frac{d}{d x} (1 + 3 cos (2 x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (1) + \frac{d}{d x} (3 cos (2 x))

\frac{d}{d x} (1) = 0

\frac{d}{d x} (3 cos (2 x)) = - 6 sin (2 x)

= 0 - 6 sin (2 x)

Simplify

= - 6 sin (2 x)

What is the derivative of 1+3cos(2x) ?
The derivative of 1+3cos(2x) is -6sin(2x)
What is the first derivative of 1+3cos(2x) ?
The first derivative of 1+3cos(2x) is -6sin(2x)