y^'= y/t-(y/t)^2

Lösung

y^{^{'}} = \frac{y}{t} - (\frac{y}{t})^{2}

y = \frac{t}{ln ( t ) + c _{1}}

Schritte zur Lösung

y^{'} (t) = \frac{y}{t} - (\frac{y}{t})^{2}

Solve Bernoulli ODE:

y = \frac{t}{ln ( t ) + c _{1}}

y = \frac{t}{ln ( t ) + c _{1}}

d er i v a t i v e 2 π r^{2}

d er i v a t i v e y = (x - 2)^{4 x}

\int \frac{x ^{3} + 3 x ^{2} - 2 x + 1}{x ^{4} + 5 x ^{2} + 4} d x

\frac{d}{d x} \frac{( x ^{2} - 1 ) ^{\frac{3}{2}}}{3 x ^{3}}

x \to 9 + lim (\frac{2}{x - 9})