What is the solution for (dy)/(dx)=sqrt(2x+y)-2 ?

The solution for (dy)/(dx)=sqrt(2x+y)-2 is y=(x^2+c_{1}^2)/4+(c_{1}x)/2-2x

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(dy)/(dx)=sqrt(2x+y)-2

\frac{d y}{d x} = 2 x + y - 2

y = \frac{x ^{2} + c _{1}^{2}}{4} + \frac{c _{1} x}{2} - 2 x

Solution steps

\frac{d y}{d x} = 2 x + y - 2

Solve using substitution:

y = \frac{x ^{2} + c _{1}^{2}}{4} + \frac{c _{1} x}{2} - 2 x

y = \frac{x ^{2} + c _{1}^{2}}{4} + \frac{c _{1} x}{2} - 2 x

What is the solution for (dy)/(dx)=sqrt(2x+y)-2 ?
The solution for (dy)/(dx)=sqrt(2x+y)-2 is y=(x^2+c_{1}^2)/4+(c_{1}x)/2-2x