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Popular Calculus >

y^'=y+2e^{-e}

Solution

y^{^{'}} = y + 2 e^{- e}

Solution

y = e^{t + c_{1} - e} - \frac{2}{e ^{e}}

Solution steps

y^{'} (t) = y + 2 e^{- e}

Solve separable ODE:

y = e^{t + c_{1} - e} - \frac{2}{e ^{e}}

y = e^{t + c_{1} - e} - \frac{2}{e ^{e}}

Graph

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Frequently Asked Questions (FAQ)

What is the solution for y^'=y+2e^{-e} ?
The solution for y^'=y+2e^{-e} is y=e^{t+c_{1}-e}-2/(e^e)