What is (\partial)/(\partial x)(x^2+zsin(xyz)) ?

The answer to (\partial)/(\partial x)(x^2+zsin(xyz)) is 2x+z^2ycos(zyx)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

(\partial)/(\partial x)(x^2+zsin(xyz))

\frac{\partial}{\partial x} (x^{2} + z sin (x yz))

2 x + z^{2} y cos (zy x)

Solution steps

\frac{\partial}{\partial x} (x^{2} + z sin (x yz))

Treat

z, y

as constants

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x^{2}) + \frac{\partial}{\partial x} (z sin (x yz))

\frac{\partial}{\partial x} (x^{2}) = 2 x

\frac{\partial}{\partial x} (z sin (x yz)) = z^{2} y cos (zy x)

= 2 x + z^{2} y cos (zy x)

What is (\partial)/(\partial x)(x^2+zsin(xyz)) ?
The answer to (\partial)/(\partial x)(x^2+zsin(xyz)) is 2x+z^2ycos(zyx)