What is the derivative of x^3-4/x ?

The derivative of x^3-4/x is 3x^2+4/(x^2)

What is the first derivative of x^3-4/x ?

The first derivative of x^3-4/x is 3x^2+4/(x^2)

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\frac{d}{d x} (x^{3} - \frac{4}{x})

3 x^{2} + \frac{4}{x ^{2}}

Solution steps

\frac{d}{d x} (x^{3} - \frac{4}{x})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) - \frac{d}{d x} (\frac{4}{x})

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (\frac{4}{x}) = - \frac{4}{x ^{2}}

= 3 x^{2} - (- \frac{4}{x ^{2}})

Simplify

= 3 x^{2} + \frac{4}{x ^{2}}

What is the derivative of x^3-4/x ?
The derivative of x^3-4/x is 3x^2+4/(x^2)
What is the first derivative of x^3-4/x ?
The first derivative of x^3-4/x is 3x^2+4/(x^2)