What is the derivative of g(x)=x^2+sin(x) ?

The derivative of g(x)=x^2+sin(x) is 2x+cos(x)

What is the first derivative of g(x)=x^2+sin(x) ?

The first derivative of g(x)=x^2+sin(x) is 2x+cos(x)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

derivative of

g (x) = x^{2} + sin (x)

2 x + cos (x)

Solution steps

\frac{d}{d x} (x^{2} + sin (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (sin (x))

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (sin (x)) = cos (x)

= 2 x + cos (x)

What is the derivative of g(x)=x^2+sin(x) ?
The derivative of g(x)=x^2+sin(x) is 2x+cos(x)
What is the first derivative of g(x)=x^2+sin(x) ?
The first derivative of g(x)=x^2+sin(x) is 2x+cos(x)