What is (\partial)/(\partial x)(x^2-10x+y^2+8) ?

The answer to (\partial)/(\partial x)(x^2-10x+y^2+8) is 2x-10

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

(\partial)/(\partial x)(x^2-10x+y^2+8)

\frac{\partial}{\partial x} (x^{2} - 10 x + y^{2} + 8)

2 x - 10

Solution steps

\frac{\partial}{\partial x} (x^{2} - 10 x + y^{2} + 8)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x^{2}) - \frac{\partial}{\partial x} (10 x) + \frac{\partial}{\partial x} (y^{2}) + \frac{\partial}{\partial x} (8)

\frac{\partial}{\partial x} (x^{2}) = 2 x

\frac{\partial}{\partial x} (10 x) = 10

\frac{\partial}{\partial x} (y^{2}) = 0

\frac{\partial}{\partial x} (8) = 0

= 2 x - 10 + 0 + 0

Simplify

= 2 x - 10

What is (\partial)/(\partial x)(x^2-10x+y^2+8) ?
The answer to (\partial)/(\partial x)(x^2-10x+y^2+8) is 2x-10