What is the integral of 1/(|x|sqrt(x^2-1)) ?

The integral of 1/(|x|sqrt(x^2-1)) is arcsec(x)+C

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral of 1/(|x|sqrt(x^2-1))

\int \frac{1}{∣ x ∣ x ^{2} - 1} d x

arcsec (x) + C

Solution steps

\int \frac{1}{∣ x ∣ x ^{2} - 1} d x

Use the common integral:

\int \frac{1}{∣ x ∣ x ^{2} - 1} d x = arcsec (x)

= arcsec (x)

Add a constant to the solution

= arcsec (x) + C

What is the integral of 1/(|x|sqrt(x^2-1)) ?
The integral of 1/(|x|sqrt(x^2-1)) is arcsec(x)+C