What is the derivative of 2x^3-3x^2-72x+15 ?

The derivative of 2x^3-3x^2-72x+15 is 6x^2-6x-72

What is the first derivative of 2x^3-3x^2-72x+15 ?

The first derivative of 2x^3-3x^2-72x+15 is 6x^2-6x-72

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\frac{d}{d x} (2 x^{3} - 3 x^{2} - 72 x + 15)

6 x^{2} - 6 x - 72

Solution steps

\frac{d}{d x} (2 x^{3} - 3 x^{2} - 72 x + 15)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{3}) - \frac{d}{d x} (3 x^{2}) - \frac{d}{d x} (72 x) + \frac{d}{d x} (15)

\frac{d}{d x} (2 x^{3}) = 6 x^{2}

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (72 x) = 72

\frac{d}{d x} (15) = 0

= 6 x^{2} - 6 x - 72 + 0

Simplify

= 6 x^{2} - 6 x - 72

What is the derivative of 2x^3-3x^2-72x+15 ?
The derivative of 2x^3-3x^2-72x+15 is 6x^2-6x-72
What is the first derivative of 2x^3-3x^2-72x+15 ?
The first derivative of 2x^3-3x^2-72x+15 is 6x^2-6x-72