What is the derivative of f(x)=sqrt(3x^2-5x+6) ?

The derivative of f(x)=sqrt(3x^2-5x+6) is (6x-5)/(2sqrt(3x^2-5x+6))

What is the first derivative of f(x)=sqrt(3x^2-5x+6) ?

The first derivative of f(x)=sqrt(3x^2-5x+6) is (6x-5)/(2sqrt(3x^2-5x+6))

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derivative of

f (x) = 3 x^{2} - 5 x + 6

\frac{6 x - 5}{2 3 x ^{2} - 5 x + 6}

Solution steps

\frac{d}{d x} (3 x^{2} - 5 x + 6)

Apply the chain rule:

\frac{1}{2 3 x ^{2} - 5 x + 6} \frac{d}{d x} (3 x^{2} - 5 x + 6)

= \frac{1}{2 3 x ^{2} - 5 x + 6} \frac{d}{d x} (3 x^{2} - 5 x + 6)

\frac{d}{d x} (3 x^{2} - 5 x + 6) = 6 x - 5

= \frac{1}{2 3 x ^{2} - 5 x + 6} (6 x - 5)

Simplify

\frac{1}{2 3 x ^{2} - 5 x + 6} (6 x - 5) : \frac{6 x - 5}{2 3 x ^{2} - 5 x + 6}

= \frac{6 x - 5}{2 3 x ^{2} - 5 x + 6}

What is the derivative of f(x)=sqrt(3x^2-5x+6) ?
The derivative of f(x)=sqrt(3x^2-5x+6) is (6x-5)/(2sqrt(3x^2-5x+6))
What is the first derivative of f(x)=sqrt(3x^2-5x+6) ?
The first derivative of f(x)=sqrt(3x^2-5x+6) is (6x-5)/(2sqrt(3x^2-5x+6))