What is the tangent of f(x)=x^2-6x,\at x=7 ?

The tangent of f(x)=x^2-6x,\at x=7 is y=8x-49

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tangent of f(x)=x^2-6x,\at x=7

tangent of

f (x) = x^{2} - 6 x, at x = 7

y = 8 x - 49

Solution steps

Find the tangent point:

(7, 7)

Find the slope of

f (x) = x^{2} - 6 x : \frac{df ( x )}{d x} = 2 x - 6

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 8

Find the line with slope m=

8

and passing through

(7, 7) : y = 8 x - 49

y = 8 x - 49

What is the tangent of f(x)=x^2-6x,\at x=7 ?
The tangent of f(x)=x^2-6x,\at x=7 is y=8x-49