integral from 0 to pi/2 of cos(4x)

Lösung

\int_{0}^{\frac{π}{2}} cos (4 x) d x

0

Schritte zur Lösung

\int_{0}^{\frac{π}{2}} cos (4 x) d x

Wende U-Substitution an

= \int_{0}^{2 π} cos (u) \frac{1}{4} d u

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{4} \cdot \int_{0}^{2 π} cos (u) d u

Nutze das gemeinsame Integral :

\int cos (u) d u = sin (u)

= \frac{1}{4} [sin (u)]_{0}^{2 π}

Berechne die Grenzen:

0

= \frac{1}{4} \cdot 0

Vereinfache

= 0

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\frac{d y}{d x} y = \frac{4 x}{3 x - 2 x ^{2}}

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