derivative of 1.4x^5-2.5x^2+6.7

解

\frac{d}{d x} (1.4 x^{5} - 2.5 x^{2} + 6.7)

7 x^{4} - 5 x

解答ステップ

\frac{d}{d x} (1.4 x^{5} - 2.5 x^{2} + 6.7)

和/差の法則を適用:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (1.4 x^{5}) - \frac{d}{d x} (2.5 x^{2}) + \frac{d}{d x} (6.7)

\frac{d}{d x} (1.4 x^{5}) = 7 x^{4}

\frac{d}{d x} (2.5 x^{2}) = 5 x

\frac{d}{d x} (6.7) = 0

= 7 x^{4} - 5 x + 0

簡素化

= 7 x^{4} - 5 x