What is area sqrt(2x+8),x,[0,9] ?

The answer to area sqrt(2x+8),x,[0,9] is 49/2+(128-16sqrt(2)-26sqrt(26))/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

area sqrt(2x+8),x,[0,9]

area

2 x + 8, x, [0, 9]

\frac{49}{2} + \frac{128 - 16 2 - 26 26}{3}

Decimal

15.43269 \dots

Solution steps

Apply the area formula:

\int_{0}^{9} 2 x + 8 - x d x

Solve

\int_{0}^{9} 2 x + 8 - x d x : \frac{49}{2} + \frac{128 - 16 2 - 26 26}{3}

The area is:

= \frac{49}{2} + \frac{128 - 16 2 - 26 26}{3}

What is area sqrt(2x+8),x,[0,9] ?
The answer to area sqrt(2x+8),x,[0,9] is 49/2+(128-16sqrt(2)-26sqrt(26))/3