What is the solution for dy-(y-3)^2dx=0 ?

The solution for dy-(y-3)^2dx=0 is y=-1/(x+c_{1)}+(3x)/(x+c_{1)}+(3c_{1})/(x+c_{1)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

dy-(y-3)^2dx=0

d y - (y - 3)^{2} d x = 0

y = - \frac{1}{x + c _{1}} + \frac{3 x}{x + c _{1}} + \frac{3 c _{1}}{x + c _{1}}

Solution steps

d y - (y - 3)^{2} d x = 0

Solve separable ODE:

y = - \frac{1}{x + c _{1}} + \frac{3 x}{x + c _{1}} + \frac{3 c _{1}}{x + c _{1}}

y = - \frac{1}{x + c _{1}} + \frac{3 x}{x + c _{1}} + \frac{3 c _{1}}{x + c _{1}}

What is the solution for dy-(y-3)^2dx=0 ?
The solution for dy-(y-3)^2dx=0 is y=-1/(x+c_{1)}+(3x)/(x+c_{1)}+(3c_{1})/(x+c_{1)}