What is the derivative of x^3-4x^2-7x+8 ?

The derivative of x^3-4x^2-7x+8 is 3x^2-8x-7

What is the first derivative of x^3-4x^2-7x+8 ?

The first derivative of x^3-4x^2-7x+8 is 3x^2-8x-7

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derivative of

x^{3} - 4 x^{2} - 7 x + 8

3 x^{2} - 8 x - 7

Solution steps

\frac{d}{d x} (x^{3} - 4 x^{2} - 7 x + 8)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) - \frac{d}{d x} (4 x^{2}) - \frac{d}{d x} (7 x) + \frac{d}{d x} (8)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (4 x^{2}) = 8 x

\frac{d}{d x} (7 x) = 7

\frac{d}{d x} (8) = 0

= 3 x^{2} - 8 x - 7 + 0

Simplify

= 3 x^{2} - 8 x - 7

What is the derivative of x^3-4x^2-7x+8 ?
The derivative of x^3-4x^2-7x+8 is 3x^2-8x-7
What is the first derivative of x^3-4x^2-7x+8 ?
The first derivative of x^3-4x^2-7x+8 is 3x^2-8x-7