(\partial)/(\partial z)(x^3+yz^2)

Lösung

\frac{\partial}{\partial z} (x^{3} + y z^{2})

2 yz

Schritte zur Lösung

\frac{\partial}{\partial z} (x^{3} + y z^{2})

Behandle

x, y

als Konstanten

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial z} (x^{3}) + \frac{\partial}{\partial z} (y z^{2})

\frac{\partial}{\partial z} (x^{3}) = 0

\frac{\partial}{\partial z} (y z^{2}) = 2 yz

= 0 + 2 yz

Vereinfache

= 2 yz

\frac{\partial}{\partial x} (cos (\frac{x}{1 + y}))

x \to 2 + lim (in t x)

\frac{d}{d θ} (sin^{2} (θ))

y^{^{''}} + 49 y = 3 tan (7 x)

t an g e n t f (x) = 2 x + 7, at x = 9