y^{''}+49y=3tan(7x)

Lösung

y^{^{''}} + 49 y = 3 tan (7 x)

y = c_{1} cos (7 x) + c_{2} sin (7 x) - \frac{3 cos ( 7 x ) ln ( tan ( 7 x ) + sec ( 7 x ) )}{49}

Schritte zur Lösung

y^{''} (x) + 49 y = 3 tan (7 x)

Solve linear ODE:

y = c_{1} cos (7 x) + c_{2} sin (7 x) - \frac{3 cos ( 7 x ) ln ( tan ( 7 x ) + sec ( 7 x ) )}{49}

y = c_{1} cos (7 x) + c_{2} sin (7 x) - \frac{3 cos ( 7 x ) ln ( tan ( 7 x ) + sec ( 7 x ) )}{49}

t an g e n t f (x) = 2 x + 7, at x = 9

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ma c l a u r in e^{- 5 x}