(dy)/(dt)=t^2-2

解答

\frac{d y}{d t} = t^{2} - 2

y = \frac{t ^{3}}{3} - 2 t + c_{1}

求解步骤

\frac{d y}{d t} = t^{2} - 2

替代

\frac{d y}{d t}

与

y^{'} (t)

y^{^{'}} (t) = t^{2} - 2

若

f^{^{'}} (x) = g (x)

则

f (x) = \int g (x) d x

y = \int t^{2} - 2 d t

\int t^{2} - 2 d t = \frac{t ^{3}}{3} - 2 t + c_{1}

y = \frac{t ^{3}}{3} - 2 t + c_{1}