What is the sum from n=1 to infinity of (ln(n))/(8n) ?

The sum from n=1 to infinity of (ln(n))/(8n) is diverges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

sum from n=1 to infinity of (ln(n))/(8n)

n = 1 \sum \infty \frac{ln ( n )}{8 n}

diverges

Solution steps

n = 1 \sum \infty \frac{ln ( n )}{8 n}

Apply the constant multiplication rule:

\sum c \cdot a_{n} = c \cdot \sum a_{n}

= \frac{1}{8} \cdot n = 1 \sum \infty \frac{ln ( n )}{n}

Apply Series Integral Test:

diverges

= \frac{1}{8} diverges

= diverges

What is the sum from n=1 to infinity of (ln(n))/(8n) ?
The sum from n=1 to infinity of (ln(n))/(8n) is diverges