(\partial)/(\partial x)(ln(y-x)-x/(y-x))

解答

\frac{\partial}{\partial x} (ln (y - x) - \frac{x}{y - x})

\frac{- 2 y + x}{( y - x ) ^{2}}

求解步骤

\frac{\partial}{\partial x} (ln (y - x) - \frac{x}{y - x})

将

y

视为常数

使用微分加减法定则:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (ln (y - x)) - \frac{\partial}{\partial x} (\frac{x}{y - x})

\frac{\partial}{\partial x} (ln (y - x)) = - \frac{1}{y - x}

\frac{\partial}{\partial x} (\frac{x}{y - x}) = \frac{y}{( y - x ) ^{2}}

= - \frac{1}{y - x} - \frac{y}{( y - x ) ^{2}}

化简

- \frac{1}{y - x} - \frac{y}{( y - x ) ^{2}} : \frac{- 2 y + x}{( y - x ) ^{2}}

= \frac{- 2 y + x}{( y - x ) ^{2}}

\frac{d}{d x} (40320 x)

\int_{- 6}^{- 10} \frac{1}{x + 2} d x

t an g e n t f (x) = x^{2} - 5, (3, 4)

d er i v a t i v e y = \frac{1}{x ^{7}}

t an g e n t f (x) = x^{2} - \frac{1}{x}, (- 1, 2)