What is the tangent of f(x)=2e^x+10x,\at x=0 ?

The tangent of f(x)=2e^x+10x,\at x=0 is y=12x+2

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tangent of f(x)=2e^x+10x,\at x=0

tangent of

f (x) = 2 e^{x} + 10 x, at x = 0

y = 12 x + 2

Solution steps

Find the tangent point:

(0, 2)

Find the slope of

f (x) = 2 e^{x} + 10 x : \frac{df ( x )}{d x} = 2 e^{x} + 10

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 12

Find the line with slope m=

12

and passing through

(0, 2) : y = 12 x + 2

y = 12 x + 2

What is the tangent of f(x)=2e^x+10x,\at x=0 ?
The tangent of f(x)=2e^x+10x,\at x=0 is y=12x+2