What is the solution for y^{''}-y^'-6y=6e^{3x}+2e^{-2x} ?

The solution for y^{''}-y^'-6y=6e^{3x}+2e^{-2x} is y=c_{1}e^{3x}+c_{2}e^{-2x}+(6e^{3x}x-2e^{-2x}x)/5

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y^{''}-y^'-6y=6e^{3x}+2e^{-2x}

y^{^{''}} - y^{^{'}} - 6 y = 6 e^{3 x} + 2 e^{- 2 x}

y = c_{1} e^{3 x} + c_{2} e^{- 2 x} + \frac{6 e ^{3 x} x - 2 e ^{- 2 x} x}{5}

Solution steps

y^{''} (x) - y^{'} (x) - 6 y = 6 e^{3 x} + 2 e^{- 2 x}

Solve linear ODE:

y = c_{1} e^{3 x} + c_{2} e^{- 2 x} + \frac{6 e ^{3 x} x - 2 e ^{- 2 x} x}{5}

y = c_{1} e^{3 x} + c_{2} e^{- 2 x} + \frac{6 e ^{3 x} x - 2 e ^{- 2 x} x}{5}

What is the solution for y^{''}-y^'-6y=6e^{3x}+2e^{-2x} ?
The solution for y^{''}-y^'-6y=6e^{3x}+2e^{-2x} is y=c_{1}e^{3x}+c_{2}e^{-2x}+(6e^{3x}x-2e^{-2x}x)/5