What is the tangent of y=(((x+2))/((x-3)))^2,\at x=4 ?

The tangent of y=(((x+2))/((x-3)))^2,\at x=4 is y=-60x+276

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tangent of y=(((x+2))/((x-3)))^2,\at x=4

tangent of

y = (\frac{( x + 2 )}{( x - 3 )})^{2}, at x = 4

y = - 60 x + 276

Solution steps

Find the tangent point:

(4, 36)

Find the slope of

y = (\frac{x + 2}{x - 3})^{2} : \frac{d y}{d x} = - \frac{10 ( x + 2 )}{( x - 3 ) ^{3}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 60

Find the line with slope m=

- 60

and passing through

(4, 36) : y = - 60 x + 276

y = - 60 x + 276

What is the tangent of y=(((x+2))/((x-3)))^2,\at x=4 ?
The tangent of y=(((x+2))/((x-3)))^2,\at x=4 is y=-60x+276