What is the solution for (dx)/(dt)=1+t-x-tx ?

The solution for (dx)/(dt)=1+t-x-tx is x=-e^{-(t^2)/2-t-c_{1}}+1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

(dx)/(dt)=1+t-x-tx

\frac{d x}{d t} = 1 + t - x - t x

x = - e^{- \frac{t ^{2}}{2} - t - c_{1}} + 1

Solution steps

\frac{d x}{d t} = 1 + t - x - t x

Solve separable ODE:

x = - e^{- \frac{t ^{2}}{2} - t - c_{1}} + 1

x = - e^{- \frac{t ^{2}}{2} - t - c_{1}} + 1

What is the solution for (dx)/(dt)=1+t-x-tx ?
The solution for (dx)/(dt)=1+t-x-tx is x=-e^{-(t^2)/2-t-c_{1}}+1