What is (\partial)/(\partial z)(-y^2sin(z)) ?

The answer to (\partial)/(\partial z)(-y^2sin(z)) is -y^2cos(z)

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(\partial)/(\partial z)(-y^2sin(z))

\frac{\partial}{\partial z} (- y^{2} sin (z))

- y^{2} cos (z)

Solution steps

\frac{\partial}{\partial z} (- y^{2} sin (z))

Treat

y

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - y^{2} \frac{\partial}{\partial z} (sin (z))

Apply the common derivative:

\frac{\partial}{\partial z} (sin (z)) = cos (z)

= - y^{2} cos (z)

What is (\partial)/(\partial z)(-y^2sin(z)) ?
The answer to (\partial)/(\partial z)(-y^2sin(z)) is -y^2cos(z)