What is the tangent of 4x^2+5x,\at x=3 ?

The tangent of 4x^2+5x,\at x=3 is y=29x-36

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tangent of 4x^2+5x,\at x=3

tangent of

4 x^{2} + 5 x, at x = 3

y = 29 x - 36

Solution steps

Find the tangent point:

(3, 51)

Find the slope of

y = 4 x^{2} + 5 x : \frac{d y}{d x} = 8 x + 5

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 29

Find the line with slope m=

29

and passing through

(3, 51) : y = 29 x - 36

y = 29 x - 36

What is the tangent of 4x^2+5x,\at x=3 ?
The tangent of 4x^2+5x,\at x=3 is y=29x-36