(x^2+2xy+y^2)dx+(2xy+x^2-1)dy=0

Lösung

(x^{2} + 2 x y + y^{2}) d x + (2 x y + x^{2} - 1) d y = 0

y = \frac{3 - 3 x ^{2} + 9 - 18 x ^{2} - 3 x ^{4} + 36 c _{1} x}{6 x}, y = \frac{3 - 3 x ^{2} - 9 - 18 x ^{2} - 3 x ^{4} + 36 c _{1} x}{6 x}

Schritte zur Lösung

(x^{2} + 2 x y + y^{2}) d x + (2 x y + x^{2} - 1) d y = 0

Solve exact ODE:

y = \frac{3 - 3 x ^{2} + 9 - 18 x ^{2} - 3 x ^{4} + 36 c _{1} x}{6 x}, y = \frac{3 - 3 x ^{2} - 9 - 18 x ^{2} - 3 x ^{4} + 36 c _{1} x}{6 x}

y = \frac{3 - 3 x ^{2} + 9 - 18 x ^{2} - 3 x ^{4} + 36 c _{1} x}{6 x}, y = \frac{3 - 3 x ^{2} - 9 - 18 x ^{2} - 3 x ^{4} + 36 c _{1} x}{6 x}