What is the tangent of y=3x^2+2x,(-1,1) ?

The tangent of y=3x^2+2x,(-1,1) is y=-4x-3

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tangent of y=3x^2+2x,(-1,1)

tangent of

y = 3 x^{2} + 2 x, (- 1, 1)

y = - 4 x - 3

Solution steps

Find the slope of

y = 3 x^{2} + 2 x : \frac{d y}{d x} = 6 x + 2

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 4

Find the line with slope m=

- 4

and passing through

(- 1, 1) : y = - 4 x - 3

y = - 4 x - 3

What is the tangent of y=3x^2+2x,(-1,1) ?
The tangent of y=3x^2+2x,(-1,1) is y=-4x-3