What is the solution for (4+x)(dy)/(dx)=y^3 ?

The solution for (4+x)(dy)/(dx)=y^3 is y=sqrt(-1/(2(ln(4+x)+c_{1)))},y=-sqrt(-1/(2(ln(4+x)+c_{1)))}

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(4+x)(dy)/(dx)=y^3

(4 + x) \frac{d y}{d x} = y^{3}

y = - \frac{1}{2 ( ln ( 4 + x ) + c _{1} )}, y = - - \frac{1}{2 ( ln ( 4 + x ) + c _{1} )}

Solution steps

(4 + x) \frac{d y}{d x} = y^{3}

Solve separable ODE:

y = - \frac{1}{2 ( ln ( 4 + x ) + c _{1} )}, y = - - \frac{1}{2 ( ln ( 4 + x ) + c _{1} )}

y = - \frac{1}{2 ( ln ( 4 + x ) + c _{1} )}, y = - - \frac{1}{2 ( ln ( 4 + x ) + c _{1} )}

What is the solution for (4+x)(dy)/(dx)=y^3 ?
The solution for (4+x)(dy)/(dx)=y^3 is y=sqrt(-1/(2(ln(4+x)+c_{1)))},y=-sqrt(-1/(2(ln(4+x)+c_{1)))}