What is the integral from 2 to 4 of (3x^2+(x^4)/4) ?

The integral from 2 to 4 of (3x^2+(x^4)/4) is 528/5

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integral from 2 to 4 of (3x^2+(x^4)/4)

\int_{2}^{4} (3 x^{2} + \frac{x ^{4}}{4}) d x

\frac{528}{5}

Decimal

105.6

Solution steps

\int_{2}^{4} 3 x^{2} + \frac{x ^{4}}{4} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{2}^{4} 3 x^{2} d x + \int_{2}^{4} \frac{x ^{4}}{4} d x

\int_{2}^{4} 3 x^{2} d x = 56

\int_{2}^{4} \frac{x ^{4}}{4} d x = \frac{248}{5}

= 56 + \frac{248}{5}

Simplify

56 + \frac{248}{5} : \frac{528}{5}

= \frac{528}{5}

What is the integral from 2 to 4 of (3x^2+(x^4)/4) ?
The integral from 2 to 4 of (3x^2+(x^4)/4) is 528/5