What is the derivative of sqrt(x^3+4x) ?

The derivative of sqrt(x^3+4x) is (3x^2+4)/(2sqrt(x^3+4x))

What is the first derivative of sqrt(x^3+4x) ?

The first derivative of sqrt(x^3+4x) is (3x^2+4)/(2sqrt(x^3+4x))

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\frac{d}{d x} (x^{3} + 4 x)

\frac{3 x ^{2} + 4}{2 x ^{3} + 4 x}

Solution steps

\frac{d}{d x} (x^{3} + 4 x)

Apply the chain rule:

\frac{1}{2 x ^{3} + 4 x} \frac{d}{d x} (x^{3} + 4 x)

= \frac{1}{2 x ^{3} + 4 x} \frac{d}{d x} (x^{3} + 4 x)

\frac{d}{d x} (x^{3} + 4 x) = 3 x^{2} + 4

= \frac{1}{2 x ^{3} + 4 x} (3 x^{2} + 4)

Simplify

\frac{1}{2 x ^{3} + 4 x} (3 x^{2} + 4) : \frac{3 x ^{2} + 4}{2 x ^{3} + 4 x}

= \frac{3 x ^{2} + 4}{2 x ^{3} + 4 x}

What is the derivative of sqrt(x^3+4x) ?
The derivative of sqrt(x^3+4x) is (3x^2+4)/(2sqrt(x^3+4x))
What is the first derivative of sqrt(x^3+4x) ?
The first derivative of sqrt(x^3+4x) is (3x^2+4)/(2sqrt(x^3+4x))