What is the solution for (dy)/(dx)+2y-8e^{-x}=0,y(0)=7 ?

The solution for (dy)/(dx)+2y-8e^{-x}=0,y(0)=7 is y= 8/(e^x)-1/(e^{2x)}

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(dy)/(dx)+2y-8e^{-x}=0,y(0)=7

\frac{d y}{d x} + 2 y - 8 e^{- x} = 0, y (0) = 7

y = \frac{8}{e ^{x}} - \frac{1}{e ^{2 x}}

Solution steps

\frac{d y}{d x} + 2 y - 8 e^{- x} = 0

Solve linear ODE:

y = \frac{8}{e ^{x}} - \frac{1}{e ^{2 x}}

y = \frac{8}{e ^{x}} - \frac{1}{e ^{2 x}}

What is the solution for (dy)/(dx)+2y-8e^{-x}=0,y(0)=7 ?
The solution for (dy)/(dx)+2y-8e^{-x}=0,y(0)=7 is y= 8/(e^x)-1/(e^{2x)}