What is the solution for y^{''}-2y=5 ?

The solution for y^{''}-2y=5 is y=c_{1}e^{sqrt(2)t}+c_{2}e^{-sqrt(2)t}-5/2

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y^{''}-2y=5

y^{^{''}} - 2 y = 5

y = c_{1} e^{2 t} + c_{2} e^{- 2 t} - \frac{5}{2}

Solution steps

y^{''} (t) - 2 y = 5

Solve linear ODE:

y = c_{1} e^{2 t} + c_{2} e^{- 2 t} - \frac{5}{2}

y = c_{1} e^{2 t} + c_{2} e^{- 2 t} - \frac{5}{2}

What is the solution for y^{''}-2y=5 ?
The solution for y^{''}-2y=5 is y=c_{1}e^{sqrt(2)t}+c_{2}e^{-sqrt(2)t}-5/2