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Popular Calculus >

integral of 1+y

Solution

\int 1 + y d y

Solution

y + \frac{y ^{2}}{2} + C

Solution steps

\int 1 + y d y

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 1 d y + \int y d y

\int 1 d y = y

\int y d y = \frac{y ^{2}}{2}

= y + \frac{y ^{2}}{2}

Add a constant to the solution

= y + \frac{y ^{2}}{2} + C

Graph

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Frequently Asked Questions (FAQ)

What is the integral of 1+y ?
The integral of 1+y is y+(y^2)/2+C