What is the d/(dθ)(2+2sin(θ)) ?

The d/(dθ)(2+2sin(θ)) is 2cos(θ)

What is the first d/(dθ)(2+2sin(θ)) ?

The first d/(dθ)(2+2sin(θ)) is 2cos(θ)

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\frac{d}{d θ} (2 + 2 sin (θ))

2 cos (θ)

Solution steps

\frac{d}{d θ} (2 + 2 sin (θ))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d θ} (2) + \frac{d}{d θ} (2 sin (θ))

\frac{d}{d θ} (2) = 0

\frac{d}{d θ} (2 sin (θ)) = 2 cos (θ)

= 0 + 2 cos (θ)

Simplify

= 2 cos (θ)