derivative f(x)=sin(4x)-cos(3x)

Lösung

ableitung von

f (x) = sin (4 x) - cos (3 x)

4 cos (4 x) + 3 sin (3 x)

Schritte zur Lösung

\frac{d}{d x} (sin (4 x) - cos (3 x))

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (sin (4 x)) - \frac{d}{d x} (cos (3 x))

\frac{d}{d x} (sin (4 x)) = cos (4 x) \cdot 4

\frac{d}{d x} (cos (3 x)) = - sin (3 x) \cdot 3

= cos (4 x) \cdot 4 - (- sin (3 x) \cdot 3)

Vereinfache

= 4 cos (4 x) + 3 sin (3 x)

\frac{d y}{d x} = x^{3} + x^{2} - 5 x + 11

\int_{1}^{1000} \frac{21}{x ^{3}} d x

y^{^{''}} - 2 y^{^{'}} + 5 y = e^{t} cos (2 t)

l a pl a ce t r an s f or m (sin (6 t) - 7)^{2}

\int \frac{cos ^{2} ( θ )}{sin ( θ )} d θ