What is the tangent of y=x^3-2x+1,(0,1) ?

The tangent of y=x^3-2x+1,(0,1) is y=-2x+1

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tangent of y=x^3-2x+1,(0,1)

tangent of

y = x^{3} - 2 x + 1, (0, 1)

y = - 2 x + 1

Solution steps

Find the slope of

y = x^{3} - 2 x + 1 : \frac{d y}{d x} = 3 x^{2} - 2

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 2

Find the line with slope m=

- 2

and passing through

(0, 1) : y = - 2 x + 1

y = - 2 x + 1

What is the tangent of y=x^3-2x+1,(0,1) ?
The tangent of y=x^3-2x+1,(0,1) is y=-2x+1