What is the solution for y^'=-2xtan(y),y(0)= pi/2 ?

The solution for y^'=-2xtan(y),y(0)= pi/2 is y=arcsin(e^{-x^2})+2pin,y=pi+arcsin(-e^{-x^2})+2pin

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y^'=-2xtan(y),y(0)= pi/2

y^{^{'}} = - 2 x tan (y), y (0) = \frac{π}{2}

y = arcsin (e^{- x^{2}}) + 2 πn, y = π + arcsin (- e^{- x^{2}}) + 2 πn

Solution steps

y^{'} (x) = - 2 x tan (y)

Solve separable ODE:

y = arcsin (e^{- x^{2}}) + 2 πn, y = π + arcsin (- e^{- x^{2}}) + 2 πn

y = arcsin (e^{- x^{2}}) + 2 πn, y = π + arcsin (- e^{- x^{2}}) + 2 πn

What is the solution for y^'=-2xtan(y),y(0)= pi/2 ?
The solution for y^'=-2xtan(y),y(0)= pi/2 is y=arcsin(e^{-x^2})+2pin,y=pi+arcsin(-e^{-x^2})+2pin