What is the derivative of 16^x ?

The derivative of 16^x is ln(2)*2^{4x+2}

What is the first derivative of 16^x ?

The first derivative of 16^x is ln(2)*2^{4x+2}

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derivative of

1 6^{x}

ln (2) \cdot 2^{4 x + 2}

Solution steps

\frac{d}{d x} (1 6^{x})

Apply the derivative exponent rule:

\frac{d}{d x} (a^{x}) = a^{x} ln (a)

= 1 6^{x} ln (16)

Simplify

1 6^{x} ln (16) : ln (2) \cdot 2^{4 x + 2}

= ln (2) \cdot 2^{4 x + 2}

What is the derivative of 16^x ?
The derivative of 16^x is ln(2)*2^{4x+2}
What is the first derivative of 16^x ?
The first derivative of 16^x is ln(2)*2^{4x+2}