What is the derivative of f(x)=(x^3)/3+x^2+4x-10 ?

The derivative of f(x)=(x^3)/3+x^2+4x-10 is x^2+2x+4

What is the first derivative of f(x)=(x^3)/3+x^2+4x-10 ?

The first derivative of f(x)=(x^3)/3+x^2+4x-10 is x^2+2x+4

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derivative of

f (x) = \frac{x ^{3}}{3} + x^{2} + 4 x - 10

x^{2} + 2 x + 4

Solution steps

\frac{d}{d x} (\frac{x ^{3}}{3} + x^{2} + 4 x - 10)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{x ^{3}}{3}) + \frac{d}{d x} (x^{2}) + \frac{d}{d x} (4 x) - \frac{d}{d x} (10)

\frac{d}{d x} (\frac{x ^{3}}{3}) = x^{2}

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (4 x) = 4

\frac{d}{d x} (10) = 0

= x^{2} + 2 x + 4 - 0

Simplify

= x^{2} + 2 x + 4

What is the derivative of f(x)=(x^3)/3+x^2+4x-10 ?
The derivative of f(x)=(x^3)/3+x^2+4x-10 is x^2+2x+4
What is the first derivative of f(x)=(x^3)/3+x^2+4x-10 ?
The first derivative of f(x)=(x^3)/3+x^2+4x-10 is x^2+2x+4