y^{''}-14y^'+51y=0

Lösung

y^{^{''}} - 14 y^{^{'}} + 51 y = 0

y = e^{7 t} (c_{1} cos (2 t) + c_{2} sin (2 t))

Schritte zur Lösung

y^{''} (t) - 14 y^{'} (t) + 51 y = 0

Solve linear ODE:

y = e^{7 t} (c_{1} cos (2 t) + c_{2} sin (2 t))

y = e^{7 t} (c_{1} cos (2 t) + c_{2} sin (2 t))

\int \frac{7 x}{x ^{2} + 4} d x

\frac{\partial}{\partial x} (x^{3} y^{2} - 2 x e^{x y})

\int cot (y) csc^{2} (y) d y

x \to 0 lim (\frac{arcsin ( x )}{7 x})

t \to 0 lim (\frac{e ^{8 t} - 1}{t})