What is the integral of (e^{1/(x^2)}+2x+ln(x))/(x^3) ?

The integral of (e^{1/(x^2)}+2x+ln(x))/(x^3) is -1/2 e^{1/(x^2)}-2/x-(ln(x))/(2x^2)-1/(4x^2)+C

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integral of (e^{1/(x^2)}+2x+ln(x))/(x^3)

\int \frac{e ^{\frac{1}{x ^{2}}} + 2 x + ln ( x )}{x ^{3}} d x

- \frac{1}{2} e^{\frac{1}{x ^{2}}} - \frac{2}{x} - \frac{ln ( x )}{2 x ^{2}} - \frac{1}{4 x ^{2}} + C

Solution steps

\int \frac{e ^{\frac{1}{x ^{2}}} + 2 x + ln ( x )}{x ^{3}} d x

Expand

\frac{e ^{\frac{1}{x ^{2}}} + 2 x + ln ( x )}{x ^{3}} : \frac{e ^{\frac{1}{x ^{2}}}}{x ^{3}} + \frac{2}{x ^{2}} + \frac{ln ( x )}{x ^{3}}

= \int \frac{e ^{\frac{1}{x ^{2}}}}{x ^{3}} + \frac{2}{x ^{2}} + \frac{ln ( x )}{x ^{3}} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int \frac{e ^{\frac{1}{x ^{2}}}}{x ^{3}} d x + \int \frac{2}{x ^{2}} d x + \int \frac{ln ( x )}{x ^{3}} d x

\int \frac{e ^{\frac{1}{x ^{2}}}}{x ^{3}} d x = - \frac{1}{2} e^{\frac{1}{x ^{2}}}

\int \frac{2}{x ^{2}} d x = - \frac{2}{x}

\int \frac{ln ( x )}{x ^{3}} d x = - \frac{ln ( x )}{2 x ^{2}} - \frac{1}{4 x ^{2}}

= - \frac{1}{2} e^{\frac{1}{x ^{2}}} - \frac{2}{x} - \frac{ln ( x )}{2 x ^{2}} - \frac{1}{4 x ^{2}}

Add a constant to the solution

= - \frac{1}{2} e^{\frac{1}{x ^{2}}} - \frac{2}{x} - \frac{ln ( x )}{2 x ^{2}} - \frac{1}{4 x ^{2}} + C

What is the integral of (e^{1/(x^2)}+2x+ln(x))/(x^3) ?
The integral of (e^{1/(x^2)}+2x+ln(x))/(x^3) is -1/2 e^{1/(x^2)}-2/x-(ln(x))/(2x^2)-1/(4x^2)+C