What is the integral of sin(2x-3) ?

The integral of sin(2x-3) is -1/2 cos(2x-3)+C

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integral of sin(2x-3)

\int sin (2 x - 3) d x

- \frac{1}{2} cos (2 x - 3) + C

Solution steps

\int sin (2 x - 3) d x

Apply u-substitution

= \int sin (u) \frac{1}{2} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int sin (u) d u

Use the common integral:

\int sin (u) d u = - cos (u)

= \frac{1}{2} (- cos (u))

Substitute back

u = 2 x - 3

= \frac{1}{2} (- cos (2 x - 3))

Simplify

= - \frac{1}{2} cos (2 x - 3)

Add a constant to the solution

= - \frac{1}{2} cos (2 x - 3) + C

What is the integral of sin(2x-3) ?
The integral of sin(2x-3) is -1/2 cos(2x-3)+C